AngularJS表单数据未存储在MySQL数据库中

在我的AngularJS应用程序中，点击提交按钮后，表单中输入的数据不会存储在MySQL数据库中。但是，成功提交表单数据后的警报表明它正在工作。

此外，在点击提交按钮后，我希望应用程序进入下一个视图（#/setup-step2），但它仍停留在步骤1。

html部分（#/setup-step1）：

<form ng-submit="submitForm1()">
Job title: <input type="text" name="jobtitle" ng-model="formData1.jobtitle">
Vacancy ID: <input type="text" name="vacancyid" ng-model="formData1.vacancyid">
<button type="submit" class="animatedbutton"> Proceed </button>
</form>

controller.js:

var ctr = angular.module('myApp.controller', []);
ctr.controller
('Step1Controller', ['$scope', '$routeParams', '$http', function($scope, $routeParams, $http){
 $scope.formData1 = {};
                        $scope.submitForm1 = function() {
                        $http({
                            method: 'POST',
                            url: 'php/setup-step1.php',
                            data: $.param($scope.formData1),
                            headers: { 'Content-Type': 'application/x-www-form-urlencoded'}
                        })
                            .success(function(data){
                                console.log(data);
                                alert("It worked");
                            })
                            .error(function(data) {
                                console.log(data);
                                alert("It didn't work");
                            })
                    }
}]);

文件夹/php:中的setup-step1.php

<?php
include_once('db.php');
// Check connection
if(mysqli_connect_errno())
  {echo '<p>Connection to MySQL server failed: '.mysqli_connect_error().'</p>';}
else
  {echo '<p>Connection to MySQL server successful.</p>';}
$_POST = json_decode(file_get_contents("php://input"), true);
if (empty($_POST['jobtitle'])) 
   {$errors['jobtitle'] = 'Job title is required.';}
else {
// Escape user inputs for security
   $jobtitle = $_POST['jobtitle'];
   $vacancyid = $_POST['vacancyid'];
   $data = "INSERT INTO campaign (Job_title, Job_id) VALUES ('$jobtitle','$vacancyid')";mysql_query("INSERT INTO campaign (Job_title, Job_id) VALUES ('$jobtitle', '$vacancyid')");}
if ($connect->query($data) === TRUE) 
   {$conn->close();} 
else 
   {echo "Error: " . $sql . "<br>" . $conn->error;}
exit();
?>