我在这里使用了教程http://tech.cibul.net/geocode-with-google-maps-api-v3/创建一个带有地图和可拖动标记的页面,以显示地址和纬度/经度。
演示-http://www.calcunation.com/testgeo.php
如何捕获这些结果并将其放入php变量中,以便插入mysql数据库?
我对Java还比较陌生,对PHP也比较熟悉。
您是否试图拆分地址组件?
就像街道,城市,州,邮编。。。。
如果是这样的话…您将需要查看地理编码的结果,并通过它返回的地址类型数组进行解析。
以下是一些您可以使用的快速示例代码。。。
//Startup a new geocode instance
var geocoder = new google.maps.Geocoder();
//event.latLng is a latLng object passed into the geocode function to get
your addy results
geocoder.geocode({'location': event.latLng}, function(results, status) {
//Show the results here
console.log(results);
if (status == google.maps.GeocoderStatus.OK) {
var addressResults = results[0].address_components;
var address1 = "";
var address2 = "";
var city = "";
var state = "";
var zipCode = "";
for(var i = 0; i < addressResults.length; i++){
for(var j = 0; j < addressResults[i].types.length; j++){
if(addressResults[i].types[j] == 'street_number'){
address1 = addressResults[i].long_name;
break;
}
if(addressResults[i].types[j] == 'route'){
address1 += " " + addressResults[i].long_name;
break;
}
if(addressResults[i].types[j] == 'subpremise'){
address2 = addressResults[i].long_name;
break;
}
if(addressResults[i].types[j] == 'locality'){
city = addressResults[i].long_name;
break;
}
if(addressResults[i].types[j] == 'administrative_area_level_1'){
state = addressResults[i].short_name;
break;
}
if(addressResults[i].types[j] == 'postal_code'){
zipCode = addressResults[i].long_name;
break;
}
}
}
//Do ajax post to your form here with the data you just parsed out
}
});