隐藏类型代码点火器的表单验证错误

这是接下来的问题

情况是：在我添加了一个隐藏字段后，现在我可以更新，但我不能保存，因为每次我尝试保存时，这个错误消息都会不断出现：The User ID field is required.

这是控制器，功能添加用于保存，更新用于更新：

function add(){
    //set common properties 
    $data['title'] = 'Tambah User baru';
    $data['action'] = site_url('user/add');
    $data['link_back'] = anchor('user/index/', 'Back to User list', array('class'=>'back'));
    //bedakan add/update
    $data['validate'] = 'add';
    $this->_set_rules();
    //run validation
    if($this->form_validation->run() == false){
        $data['message'] = '';
        $data['title'] = 'Add new User';
        //$data['message'] = '';
        $data['user']['ID_user'] = '';
        $data['user']['pass'] = '';
        $data['user']['nama'] = '';
        $data['user']['email'] = '';
        $data['user']['active'] = '';
        $data['link_back'] = anchor('user/index/', 'Lihat daftar User', array('class'=>'back'));
        $this->load->view('user_form_v', $data);
    }
    else{
        //save data
        $user = array('ID_user'=>$this->input->post('ID_user'),
        'pass'=>sha1($this->input->post('pass')),
        'nama'=>$this->input->post('nama'),
        'email'=>$this->input->post('email'),
        'active'=>$this->input->post('active'),
        'regis_date'=>date('Y-m-d H:i:s'));
        $ID_user = $this->user_m->save($user);
        //set form input nama = "id"
        $this->validation->ID_user = $ID_user;
        redirect('user/index/add_success');
    }
}
function update($ID_user){
    //set common properties
    $data['title'] = 'Update user';
    $this->load->library('form_validation');
    //set validation properties
    $this->_set_rules();
    $data['action'] = ('user/update/'.$ID_user);
    //bedakan add/update
    $data['validate'] = 'update';
    //run validation
    if ($this->form_validation->run() == false){
        $data['message'] = '';
        $data['user'] = $this->user_m->get_by_id($ID_user)->row_array();
        //set common properties
        $data['title'] = 'Update User';
        $data['message'] = '';
    }
    else{
        //save data
        $ID_user = $this->input->post('ID_user');
        $user = array(
        'pass'=>$this->input->post('pass'),
        'nama'=>$this->input->post('nama'),
        'email'=>$this->input->post('email'),
        'active'=>$this->input->post('active'),
        'regis_date'=>date('Y-m-d H:i:s'));
        $this->user_m->update($ID_user, $user);
        $data['user'] = $this->user_m->get_by_id($ID_user)->row_array();
        //set user message
        $data['message'] = 'Update User Success!';
    }
    $data['link_back'] = anchor('user/index/', 'Lihat daftar user', array('class'=>'back'));
    //load view
    $this->load->view('user_form_v', $data);
}

这是我的观点：

<input type="text" name="ID_user" class="text"
                <?php if($validate!='add'){echo "disabled";} ?>
                value="<?php echo (isset($user['ID_user']))?$user['ID_user']:""?>"/>
                <input type="hidden" name="ID_user" value="<?php echo (isset($user['ID_user']))?$user['ID_user']:""?>"/>

注意：如果输入文本和隐藏输入的名称是SAME，则更新工作但保存不工作，但如果名称不同，则更新不工作但保存工作@_@