将jquery+ajax放入PHP while循环中(所有这些都在ajax内部） - Put jquery+ajax into PHP while loop (all of which is inside of Ajax)

Put jquery+ajax into PHP while loop (all of which is inside of Ajax)

我有一个while循环，用于获取和echos状态更新。我试图在while循环中回显一个"REPOST"链接，以便它附加到任何状态更新（位于其下方），并在单击时将ID传递到外部.php文件。这个链接是jquery+ajax。

<script type="text/javascript">
$(document).on('click', 'a[id^=repost]', function(){
    var thePostID = $(this).prop('id').split('-')[1];
    //this now has the id of the $row['id'] we declared earlier.
    $.ajax({
        url: 'reposthandler.php',
        type: 'POST',
        data: {'id' : thePostID},
        success: function(data){  
        }
     });
});
</script>

<?php
include ('time.php');

$query = "SELECT poster, posterpic, category, type, date, id, follow.beingfollowed 
FROM usergen LEFT JOIN follow ON follow.beingfollowed = usergen.poster WHERE   
follow.iwannafollow 
= '*".$loggedin."' ORDER BY usergen.date DESC ";
$result = mysql_query($query) or die(mysql_error()) ;

$rows = array();
while($row = mysql_fetch_array($result)) {
    $row['ago'] = ago($row['date']);
    $rows[] = $row;

    echo '<br />';
    echo '<img src="' . $row['posterpic'] . '" width="40px" height="50px">';
    echo '<font color="red" size=2px><i>';
    echo '<a>'.$row['poster'].'</a></i></font>';
    echo '<br />';
    echo $row['category'] . ' for ' . $row['type'] . ' (' . $row['ago'] . ')';
    echo '<a href="#" id="repost-',$row['id'],'">REPOST</a>';
    echo '<br /><br /><HR size="4" width="auto" color="white">';
}
echo '</div>';
?>

链接是死的，没有链接到任何东西。为什么会这样？我需要在"成功：函数（数据）"下面添加一些内容吗？

Simply add an element to the loop for the button. 
echo '<a href="#" id="repost-',$row['id'],'"> Repost This </a>';

将click函数绑定到静态父元素。

$(document).on('click', 'a[id^=repost]', function(){
    var thePostID = $(this).prop('id').split('-')[1];
    //this now has the id of the $row['id'] we declared earlier.
    $.ajax({
        url: 'path/to/my/controller.ext?postID='+thePostID,
        type: 'POST',
        success: function(){
          //do whatever with the response.
        }
    });
});

现在，您将收到要转发的帖子的ID，您可以在后端php文件中随意处理它。