如何使用简单的html dom解析img
html5属性:data-original
$htmls = '<img class="lazy" alt="Nubifragio a Verbania , ferite 2 turiste Gravi danni, chiesto stato di calamità foto" title="Nubifragio a Verbania , ferite 2 turiste Gravi danni, chiesto stato di calamità foto" data-original="http://www.repubblica.it/images/2012/08/26/130634575-506cc9ae-11b8-4a53-920c-539a3811e46b.jpg" src="http://www.repubblica.it/static/images/homepage/2012/lazy.png" width="130" height="98" style="display: inline; ">';
$html = str_get_html($htmls);
$fata = $html->find('img');
foreach($fata as $newimage){
echo $newimage->data-original; //0
echo $newimage->src; //http://www.repubblica.it/static/images/homepage/2012/lazy.png
}
我可以得到属性src
,但data-original
返回0
$newimage->data-original;
指
$newimage->data - original;
解决这一问题的方法是尝试:
$property = 'data-original';
$newimage->$property;
或者,使用替代语法:
$newimage['data-original'];
仅供参考:
我试过了:
$newimage['data-original'];
但这对我来说是有效的:
$property = 'data-original';
$newimage->$property;
希望这能奏效
$thumbs=$video->find('img[class=images]',0)->{data original};
使用大括号会更有效率:
$newimage->{'data-original'};
另一个例子:
<?php
class foo {
var $bar = 'I am bar.';
var $arr = array('I am A.', 'I am B.', 'I am C.');
var $r = 'I am r.';
}
$foo = new foo();
$bar = 'bar';
$baz = array('foo', 'bar', 'baz', 'quux');
echo $foo->$bar . "'n";
echo $foo->{$baz[1]} . "'n";
$start = 'b';
$end = 'ar';
echo $foo->{$start . $end} . "'n";
$arr = 'arr';
echo $foo->{$arr[1]} . "'n";
?>
阅读有关用大括号括起来的变量的更多信息:PHP文档:变量