使用具有相同id的select part2将所选列值转换为另一行 - Convert selected column values to another row using select with the same id part2

Convert selected column values to another row using select with the same id part2

本文关键字：转换一行 id part2 select | 更新日期: 2023-09-27

我正在制作一个简单的时间输入和时间输出系统。。我有三双进出鞋。p_id（person_id）

表A

p_id  time_id      status            timestamp
1         1           in        2013-12-18 15:44:09
2         2           in        2013-12-18 16:23:19
1         3           out       2013-12-18 18:31:11
1         4           in        2013-12-18 18:50:11
3         5           out       2013-12-18 19:20:16
1         6           out       2013-12-18 19:50:11
2         7           out       2013-12-18 19:51:19
1         8           in        2013-12-19 07:51:19
1         9           out       2013-12-19 12:00:19
1         10          in        2013-12-19 01:00:19
1         11          out       2013-12-19 05:30:19
1         12          in        2013-12-19 07:51:19
1         13          out       2013-12-19 11:00:19

进入表格结果同一日期的一行

id status     timestamp        status     timestamp       status     timestamp          status      timestamp          status     timestamp       status      timestamp
1    in   2013-12-18 15:44:09   out   2013-12-18 18:31:11  in    2013-12-18 18:50:11    out     2013-12-18 19:50:11
2    in   2013-12-18 16:23:19   out   2013-12-18 19:51:19  
3                               out   2013-12-18 19:20:16
1    in   2013-12-19 07:51:19   out   2013-12-19 12:00:19  in    2013-12-19 01:00:19    out     2013-12-19 05:30:19     in    2013-12-19 07:51:19   out       2013-12-19 11:00:19

我想你想要这样的东西：

SELECT a1.id, a.1status, a1.timestamp, a2.status, a2.timetstamp
FROM timetable a1
LEFT JOIN timetable a2 ON a2.id=a1.id AND a2.status = 'out'
WHERE a1.status = 'in'

只有out值的行对我来说没有任何意义。

尝试此查询，

select t1.id,t2.status as IN_Status,t2.timestamp as IN_Time,t3.status as OUT_Stats,t3.timestamp as OUT_Time
  from table1 t1 
   left join table1 t2 on (t1.id=t2.id and t2.status ='in')
   left join table1 t3 on (t1.id=t3.id and t3.status ='out') 
   group by t1.id;

查看示例

SQL Fiddle示例