如何在不邮寄到实际地址的情况下测试PHP邮件功能

我会在HTML页面上创建一个简单的表单，然后将action属性指向.php文件来测试这个php脚本吗？我已经创建了PHP文件，只是不知道如何发送它。

    <?php     
    $recipients = array('name@domain.com','name@domain.com',
    'name@domain.com',
    'name@domain.com',
    ); // i will be inserting the test email here

// Assigning data from the $_POST array to variables
$name = $_POST['sender_name'];
$mail_from = $_POST['sender_email'];
$mail_to = $_POST[$recipients];
$message = $_POST['sender_message'];

// Construct email subject
$subject = 'College Newsletter: ' . $name;

// Construct email body
$body_message = 'From: ' . $name . "'r'n";
$body_message .= 'E-mail: ' . $mail_from . "'r'n";
$body_message .= 'Message: ' . $message;

// Construct email headers
$headers = 'From: ' . $name . "'r'n";
$headers .= 'Reply-To: ' . $mail_from . "'r'n";
$mail_sent = mail(implode(',',$mail_to), $subject, $body_message, $headers);
?>

服务器似乎不喜欢我的内爆方法。（见上图）我一直收到错误：警告：内爆（）[函数.内爆]：传入的参数无效我把PHP改成了这个：

    <?php     
    $to = array('name@domain.com','name@yahoo.com');
    // specify your email here

    // Assigning data from the $_POST array to variables
    $name = $_POST['name'];
    $mail_from = $_POST['mail'];
    $message = $_POST['message'];

    // Construct email subject
    $subject = 'Breaking News: ' . $name;

    // Construct email body
    $body_message = 'From: ' . $name . "'r'n";
    $body_message .= 'E-mail: ' . $mail_from . "'r'n";
    $body_message .= 'Message: ' . $message;

    // Construct email headers
    $headers = 'From: ' . $name . "'r'n";
    $headers .= 'Reply-To: ' . $mail_from . "'r'n";
    mail($to, $name, $mail_from, $message, $headers);
    ?>

现在我得到错误：警告：mail（）要求参数1为字符串，数组在第70行的bulk_mailer_test.php中给定任何人-干杯，-qs