好了,所以我使用$_GET[]从服务器通过电子邮件发送给用户的链接设置激活页面。
这是我的激活页面。
if (isset($_GET['success']) && $_GET['success'] == false) {
echo 'Your account has been activated, please login to continue.';
} else if (isset($_GET['email'], $_GET['email_code']) === true) {
$email = trim($_GET['email']);
$email_code = trim($_GET['email_code']);
if (email_exists($db, $_GET['email']) == false) {
$errors[] = 'This email address hasn''t been registered with us.';
} else if (activate($db, $email, $email_code) === false) {
$errors[] = 'We had problems activating your account, please contact an Administrator.';
}
if (empty($errors) === false) {
echo output_errors($errors);
} else {
header('Location: activate.php?success');
exit();
}
} else {
header('Location: index.php');
}
我相信是好的,问题出在我的function activate()
function activate(PDO $db, $email, $email_code) {
$stmt = $db->prepare("SELECT COUNT (`id`) FROM `users` WHERE `email` = :email AND `email_code` = :email_code AND `active` = 0");
$stmt->bindValue(':email', $email);
$stmt->bindValue(':email_code', $email_code);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_OBJ);
return $row ? $row->type : 0;
}
此刻,我只是想让它返回一些东西,但是它没有。
我真正需要的,是让它做这个。
function activate($email, $email_code) {
$email = mysql_real_escape_string($email);
$email_code = mysql_real_escape_string($email_code);
if (mysql_result(mysql_query("SELECT COUNT(`user_id`) FROM `users` WHERE `email` = '$email' AND `email_code` = '$email_code' AND `active` = 0"), 0) ==1) {
mysql_query("UPDATE `users` SET `active` = 1 WHERE `email` = '$email'");
return true;
} else {
return false;
}
}
但是我不能很好地翻译它。
请帮忙,谢谢。
我想我应该加上这不会返回任何错误,主要是因为我还没有正确地输入任何东西,让它返回一个。
编辑:else if (activate($db, $email, $email_code) === 0) {
$errors[] = 'We had problems activating your account, please contact an Administrator.';
}
则函数
function activate(PDO $db, $email, $email_code) {
$sql = "SELECT `active`, `email_code` FROM `users` WHERE `email` = '?'";
$stmt = $db->prepare($sql);
$stmt->execute(array($email));
$row = $stmt->fetch();
if ($row && $row['active'] == $email_code && !$row['active'] ) {
$sql = "UPDATE `users` SET `active` = 1 WHERE `email` = '?'";
$stmt = $db->prepare($sql);
$stmt->execute(array($email));
return $stmt->rowCount();
} else {
return 0;
}
}
function activate(PDO $db, $email, $email_code) {
$sql = "SELECT active, email_code FROM users WHERE email = ?";
$stmt = $db->prepare($sql);
$stmt->execute(array($email));
$row = $stmt->fetch();
$if ($row && $row['active'] == $email_code && !$row['active'] )
$sql = "UPDATE users SET active = 1 WHERE email = ?");
$stmt = $db->prepare($sql);
$stmt->execute(array($email));
return $stmt->rowCount();
}
}