我有一个基本的注册/登录页面，它使用php将数据提交到SQL数据库。然而，我希望页面在提交时不要借助jQueryAJAX重定向（无论成功与否）。
这是我目前拥有的，但它不起作用。它不显示任何错误消息。
HTML-注册.HTML
<!DOCTYPE html>
<html lang="en">
<head>
<title>Signup</title>
<meta charset="utf-8">
</head>
<body>
<form>
<table>
<tbody>
<tr>
<td>
<input type="text" name="first" placeholder="First Name" id="first">
</td>
</tr>
<tr>
<td>
<input type="text" name="last" placeholder="Last Name" id="last">
</td>
</tr>
<tr>
<td>
<input type="submit" value="Signup" id="signup">
</td>
</tr>
</tbody>
</table>
</form>
</body>
</html>
JavaScript-signup.js
function submit() {
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
},
error: function() {
console.log("Signup was unsuccessful");
}
});
});
}
$(document).ready(function() {
submit();
});
PHP-注册.PHP
<?php
include_once "db_connect.php";
$post_FirstName = $_POST['first'];
$post_LastName = $_POST['last'];
$addData = "INSERT INTO details (firstname, lastname) VALUES ('$post_FirstName', '$post_LastName')";
if ($conn->query($addData) === TRUE) {
echo "Working";
} else {
echo "Not working";
}
?>
这是JSFiddle。
我希望你们能帮忙。提前感谢：）
如果使用ajax，则不需要使用输入类型作为submit，请使用button。
$(document).ready(function() {
$("#signup").click(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize()
success: function() {
console.log("Signup was successful");
}
error: function() {
console.log("Signup was unsuccessful");
}
});
});
也在此更改
$post_FirstName = $_POST['first']; // name is `first` not `firstname`
您有一些制动器和括号未正确关闭
function submit() {
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
},//here
error: function() {
console.log("Signup was unsuccessful");
}
});});//here
}
$(document).ready(function() {
submit();
});
无需调用submit函数。这样就可以了，（你错过了逗号和结束标记）：
<script>
$("form").submit(function(e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: 'signup.php',
data: $('form').serialize(),
success: function() {
console.log("Signup was successful");
}, //You missed this
error: function() {
console.log("Signup was unsuccessful");
}
});
}); //You missed this
</script>