我在这里遇到了这种情况，我已经不知道了，当我上传2个图像时，文件夹中只保存了一个图像。有人能帮我写剧本吗？
$q = "SELECT h.hop_id,h.hop_name, n.ne_site_name, n.ne_site_code, f.fe_site_name, f.fe_site_code, p.photo_id, p.ne_photo_image, p.fe_photo_image
FROM hop AS h
LEFT JOIN ne_site AS n ON(h.ne_site_id = n.ne_site_id)
LEFT JOIN fe_site AS f ON(h.fe_site_id = f.fe_site_id)
LEFT JOIN photo AS p ON(h.hop_id = p.hop_id)
WHERE h.hop_id = '".$_GET['kode']."'
";
$r = mysql_query($q) or die ($q);
$data = mysql_fetch_array ($r);
$tmp_file = $_FILES[ne_photo_image][tmp_name];
$size = $_FILES[ne_photo_image][size];
$file = $_FILES[ne_photo_image][name];
$tmp_file1 = $_FILES[fe_photo_image][tmp_name];
$size1 = $_FILES[fe_photo_image][size];
$file1 = $_FILES[fe_photo_image][name];
$q = mysql_query("insert into photo(ne_photo_image,fe_photo_image,title,hop_id)
values ('$file','$file1','$_POST[photo_name_id]','$_POST[photo_hop_id]')") or die(mysql_error());
if ($q) {
} else {
echo 'gagal';
}
move_uploaded_file($tmp_file, 'image/' . $file)
这是我的表格：
<form method="post" enctype="multipart/form-data">
<table border="0"cellpadding="0" cellspacing="0" width= "100%">
<tr>
<td>Hop Name :<?echo "$data[hop_name]"?>
<input type='hidden' name='photo_hop_id' value='<?echo"$data[hop_id]"?>'>
</td>
</tr>
<table border="0"cellpadding="0" cellspacing="0" width= "100%">
<tr>
<td cellpadding="0" cellspacing="0" width= "50%">
Near End Site Name : <?echo "$data[ne_site_name]"?>
</br>
Near End Site Id : <?echo "$data[ne_site_code]"?>
</td>
<td cellpadding="0" cellspacing="0" width= "50%">
Far End Site Name : <?echo "$data[fe_site_name]"?>
</br>
Far End Site Id : <?echo "$data[fe_site_code]"?>
</td>
</tr>
<tr>
<td cellpadding="0" cellspacing="0" width= "50%">
<? $pm1= mysql_query("SELECT photo_name FROM photo_name WHERE photo_name_id = 1");
$dpm1 = mysql_fetch_array ($pm1);echo"$dpm1[0]"?>
<input type='hidden' name='photo_name_id' value='<?echo"$dpm1[0]"?>'> :
<input type="file" name="ne_photo_image">
</td>
<td cellpadding="0" cellspacing="0" width= "50%">
<?echo "$dpm1[0]"?> : <input type="file" name="fe_photo_image">
</td>
</tr>
</table>
</table>
<input type="submit" value="tambah" />
</form>
非常感谢的帮助
您只对第一个文件使用move_uploaded_file，这就是没有上传第二个图像的原因。将另一个用于第二个图像。
move_uploaded_file($tmp_file, 'image/' . $file)
move_uploaded_file($tmp_file1, 'image/' . $file1)
UDPATE：用于调试
if(! move_uploaded_file($tmp_file1, 'image/' . $file1))
{
echo $_FILES["fe_photo_image"]["error"];
}