我正在创建一个上传类,我想知道这是否正确。。例如
private $fieldname; //setting name in form
private $type = array(); //type files: text/plain','application/msword','application/pdf
private $folder; //folder where save my files
private $filename; //filename :)
public function __construct($fieldname,$type,$folder,$filename){
$this->fieldname = $fieldname;
$this->type[] = $type;
$this->folder = $folder;
$this->filename = $filename;
}
当我实例化我的对象时
$upload = new UploadClass('file',['pdf','photo'],'folder','filename');
结果不让我高兴
object(UploadClass)[1]
private 'fieldname' => string 'file' (length=4)
private 'type' =>
array (size=1)
0 =>
array (size=2)
0 => string 'pdf' (length=3)
1 => string 'photo' (length=5)
private 'folder' => string 'folder' (length=6)
private 'filename' => string 'filename' (length=8)
我认为拥有两个数组的问题并不酷。。我不知道。。也许你帮我这件事变得更好了。。对不起代码!HAHA
因为UploadClass::type
被声明为一个数组,并且您正在使用$this->type[] = $type;
向其中添加一个元素,所以您会看到结果(即嵌套数组)。基本上将该数组添加到UploadClass::type
的第一个元素中。
只需将该数组分配给UploadClass::type
,就可以完成所有设置:
$this->type = $type;